Integrand size = 25, antiderivative size = 172 \[ \int (c+d x)^2 \csc ^2(a+b x) \sin (3 a+3 b x) \, dx=-\frac {6 (c+d x)^2 \text {arctanh}\left (e^{i (a+b x)}\right )}{b}-\frac {8 d^2 \cos (a+b x)}{b^3}+\frac {4 (c+d x)^2 \cos (a+b x)}{b}+\frac {6 i d (c+d x) \operatorname {PolyLog}\left (2,-e^{i (a+b x)}\right )}{b^2}-\frac {6 i d (c+d x) \operatorname {PolyLog}\left (2,e^{i (a+b x)}\right )}{b^2}-\frac {6 d^2 \operatorname {PolyLog}\left (3,-e^{i (a+b x)}\right )}{b^3}+\frac {6 d^2 \operatorname {PolyLog}\left (3,e^{i (a+b x)}\right )}{b^3}-\frac {8 d (c+d x) \sin (a+b x)}{b^2} \]
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Time = 0.28 (sec) , antiderivative size = 172, normalized size of antiderivative = 1.00, number of steps used = 16, number of rules used = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.320, Rules used = {4516, 4493, 3377, 2718, 4268, 2611, 2320, 6724} \[ \int (c+d x)^2 \csc ^2(a+b x) \sin (3 a+3 b x) \, dx=-\frac {6 (c+d x)^2 \text {arctanh}\left (e^{i (a+b x)}\right )}{b}-\frac {6 d^2 \operatorname {PolyLog}\left (3,-e^{i (a+b x)}\right )}{b^3}+\frac {6 d^2 \operatorname {PolyLog}\left (3,e^{i (a+b x)}\right )}{b^3}-\frac {8 d^2 \cos (a+b x)}{b^3}+\frac {6 i d (c+d x) \operatorname {PolyLog}\left (2,-e^{i (a+b x)}\right )}{b^2}-\frac {6 i d (c+d x) \operatorname {PolyLog}\left (2,e^{i (a+b x)}\right )}{b^2}-\frac {8 d (c+d x) \sin (a+b x)}{b^2}+\frac {4 (c+d x)^2 \cos (a+b x)}{b} \]
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Rule 2320
Rule 2611
Rule 2718
Rule 3377
Rule 4268
Rule 4493
Rule 4516
Rule 6724
Rubi steps \begin{align*} \text {integral}& = \int \left (3 (c+d x)^2 \cos (a+b x) \cot (a+b x)-(c+d x)^2 \sin (a+b x)\right ) \, dx \\ & = 3 \int (c+d x)^2 \cos (a+b x) \cot (a+b x) \, dx-\int (c+d x)^2 \sin (a+b x) \, dx \\ & = \frac {(c+d x)^2 \cos (a+b x)}{b}+3 \int (c+d x)^2 \csc (a+b x) \, dx-3 \int (c+d x)^2 \sin (a+b x) \, dx-\frac {(2 d) \int (c+d x) \cos (a+b x) \, dx}{b} \\ & = -\frac {6 (c+d x)^2 \text {arctanh}\left (e^{i (a+b x)}\right )}{b}+\frac {4 (c+d x)^2 \cos (a+b x)}{b}-\frac {2 d (c+d x) \sin (a+b x)}{b^2}-\frac {(6 d) \int (c+d x) \cos (a+b x) \, dx}{b}-\frac {(6 d) \int (c+d x) \log \left (1-e^{i (a+b x)}\right ) \, dx}{b}+\frac {(6 d) \int (c+d x) \log \left (1+e^{i (a+b x)}\right ) \, dx}{b}+\frac {\left (2 d^2\right ) \int \sin (a+b x) \, dx}{b^2} \\ & = -\frac {6 (c+d x)^2 \text {arctanh}\left (e^{i (a+b x)}\right )}{b}-\frac {2 d^2 \cos (a+b x)}{b^3}+\frac {4 (c+d x)^2 \cos (a+b x)}{b}+\frac {6 i d (c+d x) \operatorname {PolyLog}\left (2,-e^{i (a+b x)}\right )}{b^2}-\frac {6 i d (c+d x) \operatorname {PolyLog}\left (2,e^{i (a+b x)}\right )}{b^2}-\frac {8 d (c+d x) \sin (a+b x)}{b^2}-\frac {\left (6 i d^2\right ) \int \operatorname {PolyLog}\left (2,-e^{i (a+b x)}\right ) \, dx}{b^2}+\frac {\left (6 i d^2\right ) \int \operatorname {PolyLog}\left (2,e^{i (a+b x)}\right ) \, dx}{b^2}+\frac {\left (6 d^2\right ) \int \sin (a+b x) \, dx}{b^2} \\ & = -\frac {6 (c+d x)^2 \text {arctanh}\left (e^{i (a+b x)}\right )}{b}-\frac {8 d^2 \cos (a+b x)}{b^3}+\frac {4 (c+d x)^2 \cos (a+b x)}{b}+\frac {6 i d (c+d x) \operatorname {PolyLog}\left (2,-e^{i (a+b x)}\right )}{b^2}-\frac {6 i d (c+d x) \operatorname {PolyLog}\left (2,e^{i (a+b x)}\right )}{b^2}-\frac {8 d (c+d x) \sin (a+b x)}{b^2}-\frac {\left (6 d^2\right ) \text {Subst}\left (\int \frac {\operatorname {PolyLog}(2,-x)}{x} \, dx,x,e^{i (a+b x)}\right )}{b^3}+\frac {\left (6 d^2\right ) \text {Subst}\left (\int \frac {\operatorname {PolyLog}(2,x)}{x} \, dx,x,e^{i (a+b x)}\right )}{b^3} \\ & = -\frac {6 (c+d x)^2 \text {arctanh}\left (e^{i (a+b x)}\right )}{b}-\frac {8 d^2 \cos (a+b x)}{b^3}+\frac {4 (c+d x)^2 \cos (a+b x)}{b}+\frac {6 i d (c+d x) \operatorname {PolyLog}\left (2,-e^{i (a+b x)}\right )}{b^2}-\frac {6 i d (c+d x) \operatorname {PolyLog}\left (2,e^{i (a+b x)}\right )}{b^2}-\frac {6 d^2 \operatorname {PolyLog}\left (3,-e^{i (a+b x)}\right )}{b^3}+\frac {6 d^2 \operatorname {PolyLog}\left (3,e^{i (a+b x)}\right )}{b^3}-\frac {8 d (c+d x) \sin (a+b x)}{b^2} \\ \end{align*}
Time = 0.60 (sec) , antiderivative size = 223, normalized size of antiderivative = 1.30 \[ \int (c+d x)^2 \csc ^2(a+b x) \sin (3 a+3 b x) \, dx=\frac {3 b^2 (c+d x)^2 \log \left (1-e^{i (a+b x)}\right )-3 b^2 (c+d x)^2 \log \left (1+e^{i (a+b x)}\right )+6 i b d (c+d x) \operatorname {PolyLog}\left (2,-e^{i (a+b x)}\right )-6 i b d (c+d x) \operatorname {PolyLog}\left (2,e^{i (a+b x)}\right )-6 d^2 \operatorname {PolyLog}\left (3,-e^{i (a+b x)}\right )+6 d^2 \operatorname {PolyLog}\left (3,e^{i (a+b x)}\right )+4 \cos (b x) \left (\left (-2 d^2+b^2 (c+d x)^2\right ) \cos (a)-2 b d (c+d x) \sin (a)\right )-4 \left (2 b d (c+d x) \cos (a)+\left (-2 d^2+b^2 (c+d x)^2\right ) \sin (a)\right ) \sin (b x)}{b^3} \]
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Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 480 vs. \(2 (160 ) = 320\).
Time = 2.64 (sec) , antiderivative size = 481, normalized size of antiderivative = 2.80
method | result | size |
risch | \(\frac {2 \left (x^{2} d^{2} b^{2}+2 b^{2} c d x +2 i b \,d^{2} x +b^{2} c^{2}+2 i b c d -2 d^{2}\right ) {\mathrm e}^{i \left (x b +a \right )}}{b^{3}}+\frac {2 \left (x^{2} d^{2} b^{2}+2 b^{2} c d x -2 i b \,d^{2} x +b^{2} c^{2}-2 i b c d -2 d^{2}\right ) {\mathrm e}^{-i \left (x b +a \right )}}{b^{3}}-\frac {6 d^{2} a^{2} \operatorname {arctanh}\left ({\mathrm e}^{i \left (x b +a \right )}\right )}{b^{3}}-\frac {3 d^{2} \ln \left (1-{\mathrm e}^{i \left (x b +a \right )}\right ) a^{2}}{b^{3}}+\frac {3 d^{2} \ln \left ({\mathrm e}^{i \left (x b +a \right )}+1\right ) a^{2}}{b^{3}}+\frac {3 d^{2} \ln \left (1-{\mathrm e}^{i \left (x b +a \right )}\right ) x^{2}}{b}+\frac {6 d^{2} \operatorname {polylog}\left (3, {\mathrm e}^{i \left (x b +a \right )}\right )}{b^{3}}-\frac {3 d^{2} \ln \left ({\mathrm e}^{i \left (x b +a \right )}+1\right ) x^{2}}{b}-\frac {6 d^{2} \operatorname {polylog}\left (3, -{\mathrm e}^{i \left (x b +a \right )}\right )}{b^{3}}+\frac {6 d c \ln \left (1-{\mathrm e}^{i \left (x b +a \right )}\right ) x}{b}-\frac {6 d c \ln \left ({\mathrm e}^{i \left (x b +a \right )}+1\right ) x}{b}-\frac {6 i d c \operatorname {polylog}\left (2, {\mathrm e}^{i \left (x b +a \right )}\right )}{b^{2}}+\frac {12 c d a \,\operatorname {arctanh}\left ({\mathrm e}^{i \left (x b +a \right )}\right )}{b^{2}}+\frac {6 i d^{2} \operatorname {polylog}\left (2, -{\mathrm e}^{i \left (x b +a \right )}\right ) x}{b^{2}}-\frac {6 i d^{2} \operatorname {polylog}\left (2, {\mathrm e}^{i \left (x b +a \right )}\right ) x}{b^{2}}+\frac {6 d c \ln \left (1-{\mathrm e}^{i \left (x b +a \right )}\right ) a}{b^{2}}-\frac {6 c d \ln \left ({\mathrm e}^{i \left (x b +a \right )}+1\right ) a}{b^{2}}+\frac {6 i c d \operatorname {polylog}\left (2, -{\mathrm e}^{i \left (x b +a \right )}\right )}{b^{2}}-\frac {6 c^{2} \operatorname {arctanh}\left ({\mathrm e}^{i \left (x b +a \right )}\right )}{b}\) | \(481\) |
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Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 566 vs. \(2 (156) = 312\).
Time = 0.31 (sec) , antiderivative size = 566, normalized size of antiderivative = 3.29 \[ \int (c+d x)^2 \csc ^2(a+b x) \sin (3 a+3 b x) \, dx=\frac {6 \, d^{2} {\rm polylog}\left (3, \cos \left (b x + a\right ) + i \, \sin \left (b x + a\right )\right ) + 6 \, d^{2} {\rm polylog}\left (3, \cos \left (b x + a\right ) - i \, \sin \left (b x + a\right )\right ) - 6 \, d^{2} {\rm polylog}\left (3, -\cos \left (b x + a\right ) + i \, \sin \left (b x + a\right )\right ) - 6 \, d^{2} {\rm polylog}\left (3, -\cos \left (b x + a\right ) - i \, \sin \left (b x + a\right )\right ) + 8 \, {\left (b^{2} d^{2} x^{2} + 2 \, b^{2} c d x + b^{2} c^{2} - 2 \, d^{2}\right )} \cos \left (b x + a\right ) - 6 \, {\left (i \, b d^{2} x + i \, b c d\right )} {\rm Li}_2\left (\cos \left (b x + a\right ) + i \, \sin \left (b x + a\right )\right ) - 6 \, {\left (-i \, b d^{2} x - i \, b c d\right )} {\rm Li}_2\left (\cos \left (b x + a\right ) - i \, \sin \left (b x + a\right )\right ) - 6 \, {\left (i \, b d^{2} x + i \, b c d\right )} {\rm Li}_2\left (-\cos \left (b x + a\right ) + i \, \sin \left (b x + a\right )\right ) - 6 \, {\left (-i \, b d^{2} x - i \, b c d\right )} {\rm Li}_2\left (-\cos \left (b x + a\right ) - i \, \sin \left (b x + a\right )\right ) - 3 \, {\left (b^{2} d^{2} x^{2} + 2 \, b^{2} c d x + b^{2} c^{2}\right )} \log \left (\cos \left (b x + a\right ) + i \, \sin \left (b x + a\right ) + 1\right ) - 3 \, {\left (b^{2} d^{2} x^{2} + 2 \, b^{2} c d x + b^{2} c^{2}\right )} \log \left (\cos \left (b x + a\right ) - i \, \sin \left (b x + a\right ) + 1\right ) + 3 \, {\left (b^{2} c^{2} - 2 \, a b c d + a^{2} d^{2}\right )} \log \left (-\frac {1}{2} \, \cos \left (b x + a\right ) + \frac {1}{2} i \, \sin \left (b x + a\right ) + \frac {1}{2}\right ) + 3 \, {\left (b^{2} c^{2} - 2 \, a b c d + a^{2} d^{2}\right )} \log \left (-\frac {1}{2} \, \cos \left (b x + a\right ) - \frac {1}{2} i \, \sin \left (b x + a\right ) + \frac {1}{2}\right ) + 3 \, {\left (b^{2} d^{2} x^{2} + 2 \, b^{2} c d x + 2 \, a b c d - a^{2} d^{2}\right )} \log \left (-\cos \left (b x + a\right ) + i \, \sin \left (b x + a\right ) + 1\right ) + 3 \, {\left (b^{2} d^{2} x^{2} + 2 \, b^{2} c d x + 2 \, a b c d - a^{2} d^{2}\right )} \log \left (-\cos \left (b x + a\right ) - i \, \sin \left (b x + a\right ) + 1\right ) - 16 \, {\left (b d^{2} x + b c d\right )} \sin \left (b x + a\right )}{2 \, b^{3}} \]
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Timed out. \[ \int (c+d x)^2 \csc ^2(a+b x) \sin (3 a+3 b x) \, dx=\text {Timed out} \]
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Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 413 vs. \(2 (156) = 312\).
Time = 0.42 (sec) , antiderivative size = 413, normalized size of antiderivative = 2.40 \[ \int (c+d x)^2 \csc ^2(a+b x) \sin (3 a+3 b x) \, dx=\frac {c^{2} {\left (8 \, \cos \left (b x + a\right ) - 3 \, \log \left (\cos \left (b x\right )^{2} + 2 \, \cos \left (b x\right ) \cos \left (a\right ) + \cos \left (a\right )^{2} + \sin \left (b x\right )^{2} - 2 \, \sin \left (b x\right ) \sin \left (a\right ) + \sin \left (a\right )^{2}\right ) + 3 \, \log \left (\cos \left (b x\right )^{2} - 2 \, \cos \left (b x\right ) \cos \left (a\right ) + \cos \left (a\right )^{2} + \sin \left (b x\right )^{2} + 2 \, \sin \left (b x\right ) \sin \left (a\right ) + \sin \left (a\right )^{2}\right )\right )}}{2 \, b} - \frac {12 \, d^{2} {\rm Li}_{3}(-e^{\left (i \, b x + i \, a\right )}) - 12 \, d^{2} {\rm Li}_{3}(e^{\left (i \, b x + i \, a\right )}) - 6 \, {\left (-i \, b^{2} d^{2} x^{2} - 2 i \, b^{2} c d x\right )} \arctan \left (\sin \left (b x + a\right ), \cos \left (b x + a\right ) + 1\right ) - 6 \, {\left (-i \, b^{2} d^{2} x^{2} - 2 i \, b^{2} c d x\right )} \arctan \left (\sin \left (b x + a\right ), -\cos \left (b x + a\right ) + 1\right ) - 8 \, {\left (b^{2} d^{2} x^{2} + 2 \, b^{2} c d x - 2 \, d^{2}\right )} \cos \left (b x + a\right ) - 12 \, {\left (i \, b d^{2} x + i \, b c d\right )} {\rm Li}_2\left (-e^{\left (i \, b x + i \, a\right )}\right ) - 12 \, {\left (-i \, b d^{2} x - i \, b c d\right )} {\rm Li}_2\left (e^{\left (i \, b x + i \, a\right )}\right ) + 3 \, {\left (b^{2} d^{2} x^{2} + 2 \, b^{2} c d x\right )} \log \left (\cos \left (b x + a\right )^{2} + \sin \left (b x + a\right )^{2} + 2 \, \cos \left (b x + a\right ) + 1\right ) - 3 \, {\left (b^{2} d^{2} x^{2} + 2 \, b^{2} c d x\right )} \log \left (\cos \left (b x + a\right )^{2} + \sin \left (b x + a\right )^{2} - 2 \, \cos \left (b x + a\right ) + 1\right ) + 16 \, {\left (b d^{2} x + b c d\right )} \sin \left (b x + a\right )}{2 \, b^{3}} \]
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\[ \int (c+d x)^2 \csc ^2(a+b x) \sin (3 a+3 b x) \, dx=\int { {\left (d x + c\right )}^{2} \csc \left (b x + a\right )^{2} \sin \left (3 \, b x + 3 \, a\right ) \,d x } \]
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Timed out. \[ \int (c+d x)^2 \csc ^2(a+b x) \sin (3 a+3 b x) \, dx=\text {Hanged} \]
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